Asked by Kim
In Linguistics 101, the ratio of the number of juniors to the number of seniors is 3:2. When six more juniors join the class, and one senior drops the class, the ratio of the number of juniors to the number of seniors becomes 4:1. How many students are in the class after these changes?
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Let's call the current number of juniors "3x" and the current number of seniors "2x" (since the ratio of juniors to seniors is 3:2).
After six more juniors join, we will have "3x + 6" juniors. And if one senior drops, we will have "2x - 1" seniors.
Now we're told that the new ratio of juniors to seniors is 4:1. This means that the number of juniors is four times the number of seniors. So:
3x + 6 = 4(2x - 1)
Expand the right side:
3x + 6 = 8x - 4
Subtract 3x from both sides:
6 = 5x - 4
Add 4 to both sides:
10 = 5x
Divide both sides by 5:
x = 2
So currently there are 3x = 6 juniors and 2x = 4 seniors.
After the changes, there will be 3x + 6 = 3(2) + 6 = 12 juniors and 2x - 1 = 4 - 1 = 3 seniors.
Altogether, there will be 12 + 3 = 15 students in the class after these changes.
After six more juniors join, we will have "3x + 6" juniors. And if one senior drops, we will have "2x - 1" seniors.
Now we're told that the new ratio of juniors to seniors is 4:1. This means that the number of juniors is four times the number of seniors. So:
3x + 6 = 4(2x - 1)
Expand the right side:
3x + 6 = 8x - 4
Subtract 3x from both sides:
6 = 5x - 4
Add 4 to both sides:
10 = 5x
Divide both sides by 5:
x = 2
So currently there are 3x = 6 juniors and 2x = 4 seniors.
After the changes, there will be 3x + 6 = 3(2) + 6 = 12 juniors and 2x - 1 = 4 - 1 = 3 seniors.
Altogether, there will be 12 + 3 = 15 students in the class after these changes.
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