A spring of force constant at 1500Nm-1is acted upon by a constant force of 75N calculate the potential energy stored in the spring

1 answer

The potential energy stored in a spring is given by the formula:

PE = (1/2)kx^2

Where k is the spring constant and x is the displacement from the equilibrium position.

In this case, the spring constant is 1500 N/m and the force acting on the spring is 75 N. We can use Hooke's Law to find the displacement:

F = kx
75 N = 1500 N/m * x
x = 0.05 m

Now we can use the formula for potential energy:

PE = (1/2)kx^2
PE = (1/2) * 1500 N/m * (0.05 m)^2
PE = 1.875 J

Therefore, the potential energy stored in the spring is 1.875 J.