The potential energy stored in a spring is given by the formula:
PE = (1/2)kx^2
Where k is the spring constant and x is the displacement from the equilibrium position.
In this case, the spring constant is 1500 N/m and the force acting on the spring is 75 N. We can use Hooke's Law to find the displacement:
F = kx
75 N = 1500 N/m * x
x = 0.05 m
Now we can use the formula for potential energy:
PE = (1/2)kx^2
PE = (1/2) * 1500 N/m * (0.05 m)^2
PE = 1.875 J
Therefore, the potential energy stored in the spring is 1.875 J.
A spring of force constant at 1500Nm-1is acted upon by a constant force of 75N calculate the potential energy stored in the spring
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