There is a spinner with 15 equal areas, numbered 1 through 15. If the spinner is spun one time, what is the probability that the result is a multiple of 5 or a multiple of 3?

Answer 1

There are five multiples of 3 (3, 6, 9, 12, 15) and three multiples of 5 (5, 10, 15) among the 15 numbers on the spinner. However, 15 is counted twice since it is both a multiple of 3 and a multiple of 5, so we need to subtract one from the total count.

Therefore, the probability of getting a multiple of 5 or a multiple of 3 is:

$$P(\text{multiple of 3 or 5}) = \frac{5+3-1}{15} = \frac{7}{15}$$

So the probability is $\boxed{\frac{7}{15}}$.