Question

Simplify

(p^-4+m p^2m)^-4
----------------
(p^-4)^-m

Theses are the choices

A) p-16m + 16 I say its A or B
B) p-8m – 4
C) p-11m – 4
D) p-3m + 16

Answer 1

after the p there is suppose to be a ^ for the power to sign...

Answer 2

OK, the numerator is

(p^(-4+3m))^-4 or p^(16-12m)
and the denominator is
p^4m

so the fraction becomes...
p^(16-16m) which is A

check my work.

Answer 3

this problem has been posted about 3 times in the last couple of days.

due to a lack of brackets, it was always too confusing to determine the order of operations.
Looking at your answers, I can finally conclude you meant

(p^-4+m p^2m)^-4 / (p^-4)^-m

= (p^-4+3m)^-4 / p^4m

= p^16-12m / p^4m

= p^16-16m
which is A

Answer 4

Where did you get 3m from? The problem reads

Simplify

(p^-4+m p^2m)^-4
----------------
(p^-4)^-m

Theses are the choices

A) p-16m + 16
B) p-8m – 4
C) p-11m – 4
D) p-3m + 16

I say its A or B

Answer 5

bobpursley and I both got the 3m by correctly using the rules for exponents.

Answer 6

Ok but the answer is typed incorectly choice A is

p^-16+16 not

= p^16-16m

Answer 7

Kim!
Come on!!!!

-16 + 16m vs 16m - 16 ??????

Answer 8

Is it the same thing? I don't know, but my first choice was A. I still do not understand how

(p-4+m p2m)-4 / (p-4)-m

= (p-4+3m)-4 / p4m

= p^16-12m / p^4m

where does the 12 fit in? and how does the answer end up as A?

= p16-16m

Answer 9

we used three basic rules

1. (a^x)(a^y) = a^x+y

2. (a^x)/(a^y) = a^x-y

3. (a^x)^y = a^xy

to attempt questions such as the one above without knowing those rules would be futile.

Answer 10

Thanks for your help :)