Asked by Rama ^_^
An airplane propeller slows from 14 rad/s to 1.3 rad/s as the propeller completes 14 revolutions. Find the angular acceleration of
the propeller assuming that it is a constant value.
the propeller assuming that it is a constant value.
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We can use the formula for angular acceleration:
angular acceleration = (final angular velocity - initial angular velocity) / time
First, we need to convert the number of revolutions to radians. One revolution is equal to 2π radians, so 14 revolutions is equal to 14 x 2π = 28π radians.
Then, we can plug in the values:
angular acceleration = (1.3 rad/s - 14 rad/s) / (28π / 2π) = -12.7 rad/s²
Note that the negative sign indicates that the propeller is slowing down, which makes sense given that the initial angular velocity is greater than the final angular velocity.
angular acceleration = (final angular velocity - initial angular velocity) / time
First, we need to convert the number of revolutions to radians. One revolution is equal to 2π radians, so 14 revolutions is equal to 14 x 2π = 28π radians.
Then, we can plug in the values:
angular acceleration = (1.3 rad/s - 14 rad/s) / (28π / 2π) = -12.7 rad/s²
Note that the negative sign indicates that the propeller is slowing down, which makes sense given that the initial angular velocity is greater than the final angular velocity.
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