Asked by Tante ismail
Propeller blade in aeroplane is 2m long if propeller rotates 1800rev/min compute tangential velocity.
Answers
Answered by
Henry
Circumference=pi*2r = 3.14 * 4m=12.57 m.
V = 1800rev/min * 12.57m/rev * 1min/60s=
377 m/s.
V = 1800rev/min * 12.57m/rev * 1min/60s=
377 m/s.
Answered by
Akshay
radius= 2m
Frequency= 1800 rev/min =30 Hz
Angular velocity=
2πn= 2 × 3.14 ×30
Velocity=radius×angular velocity
V=2×(2×3.14)=376.8 m/s
Frequency= 1800 rev/min =30 Hz
Angular velocity=
2πn= 2 × 3.14 ×30
Velocity=radius×angular velocity
V=2×(2×3.14)=376.8 m/s
Answered by
Sarvesh gavand
It is very easy method
Answered by
Poorvi
r=2m
V=rw
= r2πn
= 2×2×3.14×30
v=376.8 m/s
V=rw
= r2πn
= 2×2×3.14×30
v=376.8 m/s
Answered by
Pritisha
V=?
Given:
N=1800rev/min,. 1st we need to convert this in rev/sec
Therefore n=30rev/sec
Radius=2m
We know that,
V=r2πn
=2×2×3.14×30
=376.8m/s
Given:
N=1800rev/min,. 1st we need to convert this in rev/sec
Therefore n=30rev/sec
Radius=2m
We know that,
V=r2πn
=2×2×3.14×30
=376.8m/s
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