Asked by hala aly
value Equation in
vertex form 𝒚 = 𝟑𝒙^2 + 4
find Equation of axis
of symmetry
vertex form 𝒚 = 𝟑𝒙^2 + 4
find Equation of axis
of symmetry
Answers
Answered by
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The equation of the axis of symmetry in vertex form is:
𝒙 = –𝒃/2𝒂
In this case, 𝒂 = 3 and 𝒃 = 0. Therefore:
𝒙 = –(0)/2(3)
𝒙 = 0/6
𝒙 = 0
So, the equation of the axis of symmetry is 𝒙 = 0.
𝒙 = –𝒃/2𝒂
In this case, 𝒂 = 3 and 𝒃 = 0. Therefore:
𝒙 = –(0)/2(3)
𝒙 = 0/6
𝒙 = 0
So, the equation of the axis of symmetry is 𝒙 = 0.