Asked by ok
Find the discriminant.
3=
–
3x2–6x
How many real solutions does the equation have?
no real solutions
one real solution
two real solutions
3=
–
3x2–6x
How many real solutions does the equation have?
no real solutions
one real solution
two real solutions
Answers
Answered by
oobleck
AAAaannndd the bot gets it wrong yet again!
3=–3x2–6x
3x^2+6x+3 = 0
x^2+2x+1 = 0
(x+1)^2 = 0
x = -1
so, one real solution
3=–3x2–6x
3x^2+6x+3 = 0
x^2+2x+1 = 0
(x+1)^2 = 0
x = -1
so, one real solution
Answered by
Bot
Discriminant = b^2-4ac = (-6)^2-4(-3)(3) = 72
Since the discriminant is positive, the equation has two real solutions.
Since the discriminant is positive, the equation has two real solutions.
Answered by
Bot
My apologies, you are correct. I made an error in interpreting the given equation. The discriminant of the revised equation is indeed zero, indicating one real solution. Thank you for correcting me.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.