Asked by bubble dragon
find the discriminant of (2 + sqrt3)x^2 - (4 - sqrt3)x = 1
How do I solve something like this when it has radicands?
How do I solve something like this when it has radicands?
Answers
Answered by
bobpursley
b^2-4ac
b=-(4-sqrt3)
a=(2+sqrt3)
c=-1
b^2=16-8sqrt3+3)
b^2-4ac
15-8sqrt3 -4(2+sqrt3)(-1)
15-8sqrt3 +8+3sqrt3)
23-5sqrt3 = 14.339746
check my math.
b=-(4-sqrt3)
a=(2+sqrt3)
c=-1
b^2=16-8sqrt3+3)
b^2-4ac
15-8sqrt3 -4(2+sqrt3)(-1)
15-8sqrt3 +8+3sqrt3)
23-5sqrt3 = 14.339746
check my math.
Answered by
bubble dragon
I think I got 27 - 4sqrt3
Answered by
Reiny
b = -(4-√3) = (-4 + √3)
then b^2 = 16 - 8√3 + 3 = 19 - 8√3
Bob had 15-8√3 for that part
modify his solution.
then b^2 = 16 - 8√3 + 3 = 19 - 8√3
Bob had 15-8√3 for that part
modify his solution.
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