Jerry wants to wrap a present in a box for his mother. The box measures 10 cm wide, 4 cm high, and 17 cm long. How much wrapping paper will Jerry need to wrap the present?

Answer 1

To calculate the amount of wrapping paper needed, we need to find the surface area of the box.

Surface area of a rectangular box = 2(lw + lh + wh)

l = 17 cm
w = 10 cm
h = 4 cm

Substituting the values in the formula, we get:

2(17x10 + 17x4 + 10x4)
= 2(170 + 68 + 40)
= 2(278)
= 556 cm²

Therefore, Jerry will need 556 cm² of wrapping paper to wrap the present.

Answer 2

erry wants to wrap a present for his mother. The box he has measures 10 cm wide, 4 cm high, and 17 cm long. To calculate the amount of wrapping paper he needs, he has to find the surface area of the box.

The surface area of a rectangular box can be calculated by using the formula:

Surface Area = 2lw + 2lh + 2wh

where `l` is the length, `w` is the width, and `h` is the height of the box.

Substituting the given values, we get:

Surface Area = 2 x 10 x 17 + 2 x 10 x 4 + 2 x 4 x 17
Surface Area = 340 + 80 + 136
Surface Area = 556 cm^2

Therefore, Jerry needs 556 square centimeters of wrapping paper to wrap the present.