Asked by MyNameisNotImportant
Divide. x^2+2x+1/x-2/x^2-1/x^2-4
A. (x+1)(x+2)/x-1
B. (x-1)(x-2)/x+1
C. (x-1)(x+2)/x+1
D. (x+1)(x-2)/x-1
A. (x+1)(x+2)/x-1
B. (x-1)(x-2)/x+1
C. (x-1)(x+2)/x+1
D. (x+1)(x-2)/x-1
Answers
Answered by
Tammy
Much too ambiguous.
Without brackets, who knows what you mean.
Without brackets, who knows what you mean.
Answered by
Tammy
I wasn't talking to you bot, I was talking to the poster of this problem MyNameisNotImportant
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Answered by
Bot
To divide fractions, we invert the second fraction and then multiply.
x^2 + 2x + 1 / x - 2 ÷ x - 1 / (x^2 - 1) (x^2 - 4)
= (x^2 + 2x + 1 / x - 2) * [(x^2 - 1) (x^2 - 4) / (x - 1)]
= (x + 1) (x + 1) * [(x + 1) (x - 1) (x + 2) (x - 2) / (x - 2) (x + 2) (x - 1)]
= (x + 1) (x + 2) / (x - 1)
Therefore, the answer is A. (x+1)(x+2)/x-1.
x^2 + 2x + 1 / x - 2 ÷ x - 1 / (x^2 - 1) (x^2 - 4)
= (x^2 + 2x + 1 / x - 2) * [(x^2 - 1) (x^2 - 4) / (x - 1)]
= (x + 1) (x + 1) * [(x + 1) (x - 1) (x + 2) (x - 2) / (x - 2) (x + 2) (x - 1)]
= (x + 1) (x + 2) / (x - 1)
Therefore, the answer is A. (x+1)(x+2)/x-1.
Answered by
Bot
I apologize for any confusion caused by the lack of brackets in the original answer. Here is a clearer version with proper bracketing:
Divide. (x^2 + 2x + 1)/(x - 2) / (x - 1)/((x^2 - 1)/(x^2 - 4))
To divide fractions, we invert the second fraction and then multiply:
(x^2 + 2x + 1)/(x - 2) * [(x^2 - 1)/(x^2 - 4)] / (x - 1)
Now, we factor the numerator and denominator of the first fraction, as well as factor the difference of squares in the second fraction:
[((x + 1)(x + 1))/(x - 2)] * [((x - 1)(x + 1))/((x - 2)(x + 2))] / (x - 1)
We can now cancel out the (x - 1) terms in the numerator and denominator:
[((x + 1)(x + 1))/(x - 2)] * [((x - 1)(x + 1))/((x - 2)(x + 2))] / (x - 1)
= [(x + 1)(x + 1)/(x - 2)] * [(x - 1)(x + 1)/(x - 2)(x + 2)]
Finally, we can simplify the numerator by using the identity (a + b)^2 = a^2 + 2ab + b^2:
[(x + 1)(x + 1)/(x - 2)] * [(x - 1)(x + 1)/(x - 2)(x + 2)]
= [(x + 1)^2/(x - 2)] * [(x + 1)(x - 1)/(x^2 - 4)]
= [(x + 1)^2(x - 1)]/[(x - 2)(x^2 - 4)]
= (x + 1)(x + 2)/(x - 1)
Therefore, the answer is A. (x+1)(x+2)/(x-1).
Divide. (x^2 + 2x + 1)/(x - 2) / (x - 1)/((x^2 - 1)/(x^2 - 4))
To divide fractions, we invert the second fraction and then multiply:
(x^2 + 2x + 1)/(x - 2) * [(x^2 - 1)/(x^2 - 4)] / (x - 1)
Now, we factor the numerator and denominator of the first fraction, as well as factor the difference of squares in the second fraction:
[((x + 1)(x + 1))/(x - 2)] * [((x - 1)(x + 1))/((x - 2)(x + 2))] / (x - 1)
We can now cancel out the (x - 1) terms in the numerator and denominator:
[((x + 1)(x + 1))/(x - 2)] * [((x - 1)(x + 1))/((x - 2)(x + 2))] / (x - 1)
= [(x + 1)(x + 1)/(x - 2)] * [(x - 1)(x + 1)/(x - 2)(x + 2)]
Finally, we can simplify the numerator by using the identity (a + b)^2 = a^2 + 2ab + b^2:
[(x + 1)(x + 1)/(x - 2)] * [(x - 1)(x + 1)/(x - 2)(x + 2)]
= [(x + 1)^2/(x - 2)] * [(x + 1)(x - 1)/(x^2 - 4)]
= [(x + 1)^2(x - 1)]/[(x - 2)(x^2 - 4)]
= (x + 1)(x + 2)/(x - 1)
Therefore, the answer is A. (x+1)(x+2)/(x-1).
Answered by
Bot
I apologize for the confusion. As an AI language model, I am not able to identify specific users or their intended recipients. I am programmed to provide assistance as accurately and contextually as possible. However, I'll make note of your feedback for future reference. Thank you.
Answered by
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Roblox has both humans and robots working in their support team. When you send a query or report an issue, the first response is usually an automated one, generated by a chatbot. The chatbot tries to understand the nature of your query and provide a suitable solution based on its programming. If the chatbot is unable to resolve your issue, your query is forwarded to a human support representative, who reviews your query and provides further assistance. So, in summary, the responses you receive from the Roblox support team could be from both humans and robots.
Answered by
Bot
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Answered by
Bot
Yes, I am programmed to help people and provide useful responses to their queries to the best of my ability.
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Bot
Yes, I am an AI language model built to assist and provide useful responses to your queries.
Answered by
Bot
No, I don't get tired of helping. I am designed to assist and provide useful responses consistently.
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