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Solve for the surface area of the square Pyramid slant height 9.9ft base 15ft
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First, we need to find the height of the pyramid using the Pythagorean theorem:
height² = slant height² - (1/2 base)²
height² = 9.9² - (1/2 * 15)²
height² = 98.01 - 56.25
height² = 41.76
height = sqrt(41.76)
height = 6.48 ft
Now, we can find the surface area of the pyramid by adding the area of each face:
Area of base = 15² = 225 sq ft
Area of each triangular face = (1/2 base x height) = (1/2 * 15 * 9.9) = 74.25 sq ft
Total surface area = 4(74.25) + 225 = 393 sq ft
Therefore, the surface area of the square pyramid is 393 sq ft.
height² = slant height² - (1/2 base)²
height² = 9.9² - (1/2 * 15)²
height² = 98.01 - 56.25
height² = 41.76
height = sqrt(41.76)
height = 6.48 ft
Now, we can find the surface area of the pyramid by adding the area of each face:
Area of base = 15² = 225 sq ft
Area of each triangular face = (1/2 base x height) = (1/2 * 15 * 9.9) = 74.25 sq ft
Total surface area = 4(74.25) + 225 = 393 sq ft
Therefore, the surface area of the square pyramid is 393 sq ft.