Question
The first term of a geometric progression is 6. If it's common ratio is 2,find the sixth term
Answers
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The formula for the nth term of a geometric progression is given by:
an = a1 * r^(n-1)
where an is the nth term, a1 is the first term, r is the common ratio, and n is the number of terms.
Using this formula, we can find the sixth term as follows:
a6 = 6 * 2^(6-1)
= 6 * 2^5
= 6 * 32
= 192
Therefore, the sixth term of the geometric progression with first term 6 and common ratio 2 is 192.
an = a1 * r^(n-1)
where an is the nth term, a1 is the first term, r is the common ratio, and n is the number of terms.
Using this formula, we can find the sixth term as follows:
a6 = 6 * 2^(6-1)
= 6 * 2^5
= 6 * 32
= 192
Therefore, the sixth term of the geometric progression with first term 6 and common ratio 2 is 192.