2+square root of 4-x=x
rewrite it as
√(4-x) = x-2
now square both sides
4-x = x^2 - 4x + 4
x(x-3)=0
so x = 0 or x = 3
BUT when we square an equation, all answers must be verified in the original equation
Which answer works and which doesn't?
1 answer