max/min occur when f'(x) = 0
Assuming you meant f(x) = xe^(-8x), then
f'(x) = (1-8x) e^(-8x)
So, there will be a local min/max (which?) at x = 1/8
Now check f(0) and f(2) to see whether they are global min/max.
(2 points) Consider the function f(x)=xe^−8x, 0≤x≤2.
This function has an absolute minimum value equal to:
which is attained at x=
and an absolute maximum value equal to:
which is attained at x=
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