2 liters of cleaning solution is 65% ammonia. How much water must be added to dilute it to a 40% soulition?
2 answers
1.25L of water
So, you're going to want to set up an equation and the proper concentration formula for this problem would be C1(Q1)=C2(Q2). C1 is your given concentration is 65% (0.65) and your second concentration (the desired concentration) is 40% (0.40). Your solution is 2.0L so that would be your first quantity. Your second quantity is unknown so we can write it as X. So now plug everything in! 0.65(2)=0.40(X). Then you distribute! So 1.30=0.4X. Now you divide by 0.4! So you end up with X=3.25! That would be your second value but the question asks for HOW MUCH WATER YOU NEED TO ADD! So you would subtract Q2 with Q1. 3.25-2.0=1.25. You would add 1.25L!