just use the power rule, and note thet d/dx (-1/x) = 1/x^2
∫[2,6] (1/x^2) dx = -1/x [2,6] = (-1/6)-(-1/2) = ____
∫[2,6] (1/x^2)
by hand
2 answers
∫ 1 / x² dx = - 1 / x
6
∫ 1 / x² dx =
2
- 1 / 6 - ( - 1 / 2 ) = - 1 / 6 + 1 / 2 = - 1 / 6 + 3 / 6 = 2 / 6 = 2 ∙ 1 / 2 ∙ 3 = 1 / 3
6
∫ 1 / x² dx =
2
- 1 / 6 - ( - 1 / 2 ) = - 1 / 6 + 1 / 2 = - 1 / 6 + 3 / 6 = 2 / 6 = 2 ∙ 1 / 2 ∙ 3 = 1 / 3
4 answers