2(4^x)=32^y and 125^x/25^y=625

Answer 1

2(4^x)=32^y
2*2^(2x) = 2^(5y)
2x+1 = 5y

125^x/25^y=625
5^(3x-2y) = 5^4

So now just solve
2x-5y = -1
3x-2y = 4

Answer 2

2(4^x)=32^y
(2)(2^(2x)) = (2^5)^y
2^(2x+1) = 2^(5) ----> 2x+1 = 5y , ***

125^x/25^y=625
5^(3x)/5^(2y) = 5^4
5^(3x - 2y) = 5^4 ----> 3x - 2y = 4 , ****

equation *** times 3: 6x - 15y = -3
equation **** times 2: 6x - 4y = 8

subtract these last 2 equations:
11y = 11
y = 1, but this into 2x+1 = 5y
2x + 1 = 5
x = 2