Question

2(2^1) +3(2^2) + 4(2^3)+...+n^3 = [n(n+1)/2]^2

using the mathematical induction

please help!

Answer 1

The right hand side [n(n+1)/2]^2 applies to the sum Σi³ i=1 to n.

Answer 2

The right hand side [n(n+1)/2]^2 applies to the sum Σi³ i=1 to n.

If the left hand side is correct, then it should read:

2(2^1) +3(2^2) + 4(2^3)+...+(n+1)(2ⁿ) = n*2ⁿ⁺¹

You can proceed the same way as the answer to the previous post. Feel free to show your work if you have problems.