2(2^1) +3(2^2) + 4(2^3)+...+n^3 = [n(n+1)/2]^2
using the mathematical induction
please help!
2 answers
The right hand side [n(n+1)/2]^2 applies to the sum Σi³ i=1 to n.
The right hand side [n(n+1)/2]^2 applies to the sum Σi³ i=1 to n.
If the left hand side is correct, then it should read:
2(2^1) +3(2^2) + 4(2^3)+...+(n+1)(2n) = n*2n+1
You can proceed the same way as the answer to the previous post. Feel free to show your work if you have problems.
If the left hand side is correct, then it should read:
2(2^1) +3(2^2) + 4(2^3)+...+(n+1)(2n) = n*2n+1
You can proceed the same way as the answer to the previous post. Feel free to show your work if you have problems.