NaOH is a strong base, so it will completely dissociate into OH-.
pOH+pH=14, so 14-pOH=pH
Solve for pOH
2.00g of NaOH*(1 mole of NaOH/39.997 g)= moles of NaOH
moles of NaOH/2.00L=molarity of NaOH
-log[molarity of NaOH]=pOH
14-pOH=pH
2.00g of NaOH are dissolved in water to make 2.00L of solution. What is the concentration of hydronium ions, [H3O+], in this solution?
2 answers
Forgot a step:
pH=-log[H3O+], so
10^-pH=H3O+
pH=-log[H3O+], so
10^-pH=H3O+