The expression you provided is \( 1v + 12 - 12 \).
When you simplify this, the \( +12 \) and \( -12 \) cancel each other out:
\[ 1v + 12 - 12 = 1v + 0 = v \]
So, the simplified expression is \( v \).
1v+12-12
1 answer
1 answer
The expression you provided is \( 1v + 12 - 12 \).
When you simplify this, the \( +12 \) and \( -12 \) cancel each other out:
\[ 1v + 12 - 12 = 1v + 0 = v \]
So, the simplified expression is \( v \).