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Write the equation of the parabola that has vertex (2.5, 2.75) and passes through the point (1, 5).Asked by eee
write the equation of the parabola that has its vertex at (2, 7) and passes through the point (-1, 3)
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Answered by
eee
write the equation of the parabola that has its vertex at (5, 0) and passes through the point (7, -2)
Answered by
Bot
Using the vertex form of a parabola, the equation is:
y = a(x - 2)^2 + 7
where "a" is a constant that determines the shape of the parabola.
To find "a," we can use the point (-1, 3) on the parabola:
3 = a(-1 - 2)^2 + 7
3 = a(-3)^2 + 7
3 = 9a + 7
-4 = 9a
a = -4/9
So the equation of the parabola is:
y = (-4/9)(x - 2)^2 + 7
y = a(x - 2)^2 + 7
where "a" is a constant that determines the shape of the parabola.
To find "a," we can use the point (-1, 3) on the parabola:
3 = a(-1 - 2)^2 + 7
3 = a(-3)^2 + 7
3 = 9a + 7
-4 = 9a
a = -4/9
So the equation of the parabola is:
y = (-4/9)(x - 2)^2 + 7
Answered by
Bot
Using the vertex form of a parabola, the equation is:
y = a(x - 5)^2 + 0
where "a" is a constant that determines the shape of the parabola.
To find "a," we can use the point (7, -2) on the parabola:
-2 = a(7 - 5)^2 + 0
-2 = 4a
a = -1/2
So the equation of the parabola is:
y = (-1/2)(x - 5)^2 + 0
or
y = (-1/2)x^2 + 5x - 12.5
y = a(x - 5)^2 + 0
where "a" is a constant that determines the shape of the parabola.
To find "a," we can use the point (7, -2) on the parabola:
-2 = a(7 - 5)^2 + 0
-2 = 4a
a = -1/2
So the equation of the parabola is:
y = (-1/2)(x - 5)^2 + 0
or
y = (-1/2)x^2 + 5x - 12.5
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