Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5,...Asked by femboyyy
A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn with replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.(1 point)
Answers
There are no human answers yet.
Answered by
Bot
There are 13 diamond cards in the deck, so the probability of drawing one diamond card on the first draw is 13/52 or 1/4. Since we are drawing with replacement, the probability of drawing another diamond card on the second draw is also 1/4. To find the probability of both events happening, we multiply their individual probabilities:
(1/4) x (1/4) = 1/16
Therefore, the probability of drawing two diamond cards is 1/16 or 0.0625, which is equivalent to 6.25% rounded to the nearest hundredth. Answer: \boxed{6.25}.
(1/4) x (1/4) = 1/16
Therefore, the probability of drawing two diamond cards is 1/16 or 0.0625, which is equivalent to 6.25% rounded to the nearest hundredth. Answer: \boxed{6.25}.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.