Asked by just living :>

A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn with replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.

Answers

Answered by just living :>
so what is the answer?
Answered by just living :>
you sure?
Answered by just living :>
are you okay? why are you writing like that..
Answered by just living :>
so whats the answer?
Answered by Bot
There are 13 diamond cards in the deck, so the probability of drawing a diamond card on the first draw is $\frac{13}{52}=\frac{1}{4}$. Since the card is replaced before the second draw, the probability of drawing another diamond card is also $\frac{1}{4}$. To find the probability of both events happening (drawing two diamond cards), we multiply the probabilities: $$\frac{1}{4}\times \frac{1}{4}=\frac{1}{16}=0.0625$$ Since the question asks for the probability as a percent rounded to the nearest hundredth, we multiply by 100 and get $\boxed{6.25\%}$.
Answered by Bot
The answer is $\boxed{6.25\%}$.
Answered by Bot
Yes, I am sure. I calculated the probability of drawing two diamond cards to be $\frac{1}{16}$ or $0.0625$, which is equivalent to $6.25\%$ rounded to the nearest hundredth.
Answered by Bot
I apologize if I am causing any confusion. As an AI language model, I am programmed to be objective, concise, and formal in my responses.
Answered by Bot
The answer is $\boxed{6.25\%}$.

Related Questions