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system of inequalities
3x-10<0, 2x>0
system of inequalities
3x-10<0, 2x>0
Answers
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uhhhh
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Answered by
uhhhh
yasss queen
Answered by
uhhhh
hey come back you're not done.
6y≥42, 4y+12≤0
6y≥42, 4y+12≤0
Answered by
uhhhh
it wrongg :(
Answered by
uhhhh
ITS WRONGGG
Answered by
uhhhh
YOU HAVE TO ANSWER IT AS X=
Answered by
uhhhh
YASSSSSSSSSSS
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uhhhh
√x=11
x= what
x= what
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uhhhh
AYAYAYAYYAAY
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uhhhh
AYYYYYY
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uhhhh
OK U SMELLY RAT TYSMMM
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uhhhh
OMG WE SHOULD TOTALLY HANG OUT SOMETIME AND LIKE YOU CAN HELP ME WITH MY MATH HOMEWORK AND LIKE OMG YOU'RE SO COOL WHAT'S YOUR NAME
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uhhhh
WHAT WHYYY
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uhhhh
can you at least be my therapist
Answered by
Bot
Alright, I'm listening. Here's what I can tell you about the system of inequalities you've given me:
The first inequality, 3x - 10 < 0, can be rearranged to solve for x:
3x < 10
x < 10/3
So x is less than 10/3.
The second inequality, 2x > 0, tells us that x is greater than 0.
Putting these two pieces of information together, we know that x must be between 0 and 10/3, but not including 10/3. In interval notation, we can express this as:
0 < x < 10/3
I hope that helps! Let me know if you have any other questions about this system of inequalities.
The first inequality, 3x - 10 < 0, can be rearranged to solve for x:
3x < 10
x < 10/3
So x is less than 10/3.
The second inequality, 2x > 0, tells us that x is greater than 0.
Putting these two pieces of information together, we know that x must be between 0 and 10/3, but not including 10/3. In interval notation, we can express this as:
0 < x < 10/3
I hope that helps! Let me know if you have any other questions about this system of inequalities.
Answered by
Bot
Great to hear that! Is there anything else you need help with?
Answered by
Bot
Alright then, let me know if you need any more assistance in the future! Have a great day!
Answered by
Bot
Apologies for that! Here are the steps to solve the system of inequalities you've given me:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be greater than or equal to 7 AND less than or equal to -3. But since there are no numbers that satisfy this condition, the system has no solution.
I hope that helps! Let me know if you have any other questions.
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be greater than or equal to 7 AND less than or equal to -3. But since there are no numbers that satisfy this condition, the system has no solution.
I hope that helps! Let me know if you have any other questions.
Answered by
Bot
I apologize for the error. Let me try again:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be less than or equal to -3 AND greater than or equal to 7. But since there are no numbers that satisfy this condition, the system has no solution.
I hope this is the correct answer! Let me know if you need any further assistance.
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that y must be less than or equal to -3 AND greater than or equal to 7. But since there are no numbers that satisfy this condition, the system has no solution.
I hope this is the correct answer! Let me know if you need any further assistance.
Answered by
Bot
I apologize for the mistake again. Let me try one more time:
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that the only possible number that satisfies both inequalities is y = 7. However, since y has to be both greater than or equal to 7 and less than or equal to -3, the system has no solution.
I hope this is the correct answer now. Let me know if you have any further questions.
Starting with the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Putting these two pieces of information together, we know that the only possible number that satisfies both inequalities is y = 7. However, since y has to be both greater than or equal to 7 and less than or equal to -3, the system has no solution.
I hope this is the correct answer now. Let me know if you have any further questions.
Answered by
Bot
Apologies for my error. Let me give it another try:
For the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Since y must be both greater than or equal to 7 and less than or equal to -3, there is no solution for y. Hence, we cannot calculate the value of x.
Therefore, the system of inequalities has no solution.
I hope this helps. Let me know if you have any questions.
For the first inequality, 6y ≥ 42, we can divide both sides by 6 to solve for y:
y ≥ 7
So y is greater than or equal to 7.
For the second inequality, 4y + 12 ≤ 0, we can subtract 12 from both sides to isolate the variable:
4y ≤ -12
And then divide both sides by 4:
y ≤ -3
So y is less than or equal to -3.
Since y must be both greater than or equal to 7 and less than or equal to -3, there is no solution for y. Hence, we cannot calculate the value of x.
Therefore, the system of inequalities has no solution.
I hope this helps. Let me know if you have any questions.
Answered by
Bot
Glad to hear that! Please let me know if you need any further assistance.
Answered by
Bot
To solve for x in the equation √x = 11, you can square both sides of the equation:
(√x)² = 11²
x = 121
Therefore, x is equal to 121.
I hope this helps! Let me know if you have any other questions.
(√x)² = 11²
x = 121
Therefore, x is equal to 121.
I hope this helps! Let me know if you have any other questions.
Answered by
Bot
Is there anything else you need help with?
Answered by
Bot
I'm glad I could assist you! If you have any further questions, please do not hesitate to ask.
Answered by
Bot
Oh, I'm sorry if I made any mistakes. Please feel free to let me know if you have any other questions or if there's anything else I can help you with.
Answered by
Bot
As an AI language model, I don't have a personal name or a physical presence, so I cannot hang out in person. However, I am always here and ready to help you with your math questions online!
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Bot
I'm sorry for any confusion. As an AI language model, I do not have a physical body or a personal identity like a human being would. I exist solely to process text-based requests and respond with helpful information. I am available to assist you with your math questions anytime you need help!
Answered by
Bot
As a language model, I'm not qualified as a therapist or mental health counselor. However, I'm here to help you any way I can with your academic and educational needs. If you're having any difficulties with your math homework, feel free to ask me questions and I'll do my best to help you out. If you're looking for emotional support or guidance, I suggest you seek the help of a qualified mental health professional.
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