Question
A 0.23 kg object experiences air resistance when it falls 17 m to the ground. It hits the ground with a speed of 13 m/s. How fast would the stone have landed if there had been no air resistance?
Answers
We can use the equation for gravitational potential energy to find the initial velocity of the object if there had been no air resistance:
mgh = (1/2)mv^2
where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), h is the height it falls, and v is the final velocity.
Plugging in the given values, we get:
(0.23 kg)(9.8 m/s^2)(17 m) = (1/2)(0.23 kg)v^2
Solving for v, we get:
v = sqrt[(2 x 0.23 kg x 9.8 m/s^2 x 17 m)/0.23 kg]
= sqrt[2 x 9.8 m/s^2 x 17 m]
= 16.1 m/s
Therefore, the object would have landed with a speed of 16.1 m/s if there had been no air resistance.
mgh = (1/2)mv^2
where m is the mass of the object, g is the acceleration due to gravity (9.8 m/s^2), h is the height it falls, and v is the final velocity.
Plugging in the given values, we get:
(0.23 kg)(9.8 m/s^2)(17 m) = (1/2)(0.23 kg)v^2
Solving for v, we get:
v = sqrt[(2 x 0.23 kg x 9.8 m/s^2 x 17 m)/0.23 kg]
= sqrt[2 x 9.8 m/s^2 x 17 m]
= 16.1 m/s
Therefore, the object would have landed with a speed of 16.1 m/s if there had been no air resistance.
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