Asked by N
Solve for x.
3x-1/x+3 +3= 4x/x-3
3x-1/x+3 +3= 4x/x-3
Answers
There are no human answers yet.
Answered by
Bot
We start by combining the fraction on the left side and the fraction on the right side. We note that the lowest common denominator for both fractions is (x+3)(x-3). So we get,
3x-1/x+3 +3= (3x-1)(x-3)/(x+3)(x-3) +3(x+3)(x-3)/(x+3)(x-3)
4x/x-3 =4x(x+3)/(x+3)(x-3)
Now that both fractions have the same denominator, we can equate the numerators
(3x-1)(x-3) +3(x+3)(x-3) = 4x(x+3)
3x^2 - 10x + 3 + 3x^2 -9x = 4x^2 + 12x
6x^2 - 19x + 3= 4x^2 + 12x
2x^2 - 31x + 3= 0
Now, we solve the quadratic equation 2x^2 - 31x + 3= 0. Using the quadratic formula, we get
x = (31 ± sqrt(31^2 - 4*2*3)) / (2*2)
x = (31 ± sqrt(937)) / 4
The two possible values of x are (31 + sqrt(937))/4 and (31- sqrt(937))/4.
3x-1/x+3 +3= (3x-1)(x-3)/(x+3)(x-3) +3(x+3)(x-3)/(x+3)(x-3)
4x/x-3 =4x(x+3)/(x+3)(x-3)
Now that both fractions have the same denominator, we can equate the numerators
(3x-1)(x-3) +3(x+3)(x-3) = 4x(x+3)
3x^2 - 10x + 3 + 3x^2 -9x = 4x^2 + 12x
6x^2 - 19x + 3= 4x^2 + 12x
2x^2 - 31x + 3= 0
Now, we solve the quadratic equation 2x^2 - 31x + 3= 0. Using the quadratic formula, we get
x = (31 ± sqrt(31^2 - 4*2*3)) / (2*2)
x = (31 ± sqrt(937)) / 4
The two possible values of x are (31 + sqrt(937))/4 and (31- sqrt(937))/4.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.