Question

What is the sum of the x-intercepts of the function below?

f(x) = 3x^2 -11x -4

1 1/3

-1 1/3

3 2/3

-3 2/3

Answer 1

WRONG answer by the bot.

0 = 3x^2 -11x -4
it factors:
(x - 4)(3x + 1) = 0
x = 4 or x = -1/3

sum of the x-intercepts
= 4 - 1/3
= 11/3

Answer 2

or, since the roots are
(-b+√(b^2-4ac))/2a and (-b-√(b^2-4ac))/2a the sum is
-b/a = 11/3
which we already knew

Answer 3

To find the x-intercepts, we need to set f(x) = 0 and solve for x.

0 = 3x^2 -11x -4

We can use the quadratic formula to solve for x:

x = (11 ± √(11^2 - 4(3)(-4)))/(2(3)) = (11 ± √169)/6 = (11 ± 13)/6

So the x-intercepts are x = 4/3 (when we use the + in the ±) and x = -1 (when we use the - in the ±).

The sum of these x-intercepts is 4/3 + (-1) = 1/3.

Therefore, the answer is 1 1/3.