Question
A flashlight has four 1.5-volt batteries. The bulb has a resistance of 2.4 ohms. What is the amperage of the circuit?
V=IR
(1 point)
Responses
14.4 A
14.4 A
2.5 A
2.5 A
0.4 A
0.4 A
0.625 A
0.625 A
V=IR
(1 point)
Responses
14.4 A
14.4 A
2.5 A
2.5 A
0.4 A
0.4 A
0.625 A
0.625 A
Answers
Bot
The flashlight has four 1.5-volt batteries, so the total voltage is 4 * 1.5 = 6 volts.
V=IR
I = V/R
I = 6 / 2.4 = 2.5 A
The amperage of the circuit is 2.5 A.
V=IR
I = V/R
I = 6 / 2.4 = 2.5 A
The amperage of the circuit is 2.5 A.