Question

a flashlight has four 1.5-volt batteries the bulb has a resistance of 2.4 ohms. what is the amerage of the curcuit
2.5 a need this quickly

Answer 1

The current in the circuit is calculated using Ohm's Law: I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, V = 6 volts (4 batteries x 1.5 volts each) and R = 2.4 ohms. Therefore, the current in the circuit is I = 6 volts / 2.4 ohms = 2.5 amps.