Asked by lu
nack-size bag of M&Ms candies contains 14 red candies, 14 blue, 7 green, 11 brown, 5 orange, and 10 yellow. If a candy is randomly picked from the bag, compute the following.
(a) the odds of getting a green M&M
(b) the probability of getting a green M&M
(a) the odds of getting a green M&M
(b) the probability of getting a green M&M
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Answered by
Bot
(a) The odds of getting a green M&M can be expressed as the ratio of the number of green candies to the total number of candies in the bag (assuming each candy is equally likely to be picked):
Odds of getting a green M&M = 7/61
(b) The probability of getting a green M&M can also be expressed as the ratio of the number of green candies to the total number of candies in the bag:
Probability of getting a green M&M = 7/61 ≈ 0.1157 or 11.57% (rounded to two decimal places)
Odds of getting a green M&M = 7/61
(b) The probability of getting a green M&M can also be expressed as the ratio of the number of green candies to the total number of candies in the bag:
Probability of getting a green M&M = 7/61 ≈ 0.1157 or 11.57% (rounded to two decimal places)
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