Asked by 20four
A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a red candy?
3 to 7
4 to 3
4 to 7
can someone show me how to find the correct answer (Not the answer) but the steps ?!!!
3 to 7
4 to 3
4 to 7
can someone show me how to find the correct answer (Not the answer) but the steps ?!!!
Answers
Answered by
Reiny
the "odds" of some event is very closely tied in with finding probabilities.
in this case you want the
odds against some event.
so find the probability in favour of the event
then the probability against that event
The odds against the event = (the probability against that event ) : (the probability in favour of the event)
once you do your arithmetic you will realize that the denominators with cancel
e.g. the prob of some event = 4/7
then the prob against that event = 1 - 4/7 = 3/7
the odds in favour of the event = 4/7 : 3/7 = 4 : 3
note that the odds against the event = 3/7 : 4/7 = 3 : 4
in this case you want the
odds against some event.
so find the probability in favour of the event
then the probability against that event
The odds against the event = (the probability against that event ) : (the probability in favour of the event)
once you do your arithmetic you will realize that the denominators with cancel
e.g. the prob of some event = 4/7
then the prob against that event = 1 - 4/7 = 3/7
the odds in favour of the event = 4/7 : 3/7 = 4 : 3
note that the odds against the event = 3/7 : 4/7 = 3 : 4
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