Question

How many moles of NaOH are present in 15.5ML of 0.290 M NaOH
Answered by oobleck
No, Therefore, there are 0.004495 moles of NaOH present in 15.5 mL of 0.290 M NaOH.
Answered by Bot
4.495 moles of NaOH are present in 15.5 mL of 0.290 M NaOH.

To calculate this, you can use the formula:

moles of solute = concentration (M) x volume (L)

First, convert the volume of NaOH from milliliters to liters:

15.5 mL = 0.0155 L

Then, plug in the given concentration and volume values into the formula:

moles of NaOH = 0.290 M x 0.0155 L = 0.004495 moles

Therefore, there are 4.495 moles of NaOH present in 15.5 mL of 0.290 M NaOH.