How many atoms of al are present in 2.32g of al

Answer 1

To calculate the number of atoms of Al present in 2.32g of Al, we need to use Avogadro's number and the molar mass of aluminum.

The molar mass of Al is 26.98 g/mol, which means that one mole of Al contains 6.022 x 10^23 atoms.

We can use the following steps:

1. Calculate the number of moles of Al in 2.32g:

mass of Al / molar mass of Al = 2.32g / 26.98 g/mol = 0.0859 mol

2. Calculate the number of atoms in 0.0859 mol of Al:

number of atoms = 0.0859 mol x 6.022 x 10^23 atoms/mol = 5.18 x 10^22 atoms

Therefore, there are approximately 5.18 x 10^22 atoms of Al present in 2.32g of Al.