To determine the number of chlorine atoms present in MgCl2, we need to examine the chemical formula of magnesium chloride.
The chemical formula for magnesium chloride, MgCl2, tells us that there are two chlorine atoms in each molecule of magnesium chloride.
Therefore, if we have 5.90 of MgCl2, we can multiply this by the number of chlorine atoms per molecule to find the total number of chlorine atoms:
Number of Cl atoms = 5.90 MgCl2 * 2 Cl atoms/MgCl2
Number of Cl atoms = 11.80
Therefore, there are 11.80 chlorine atoms present in 5.90 of MgCl2.
Number of chlorine atoms present in the MgCL2 produced which is 5.90
3 answers
I assume that is 5.90 g MgCl2 produced.
moles MgCl2 present in 5.90 g = grams MgCl2/molar mass MgCl2 = 5.90/95.2 = apprixunately 0.062.
There are 0.062 mols MgCl2 x (6.022 x 10^23 molecules/1 mol) = approximately 3.7E22 molecles MgCl2.
# Cl atoms = approximately 3.7E22 molecules MgCl2 x (2 Cl atoms/1 mol MgCl2) = approximately 3.7E22 x 2 = about 7.4E22 atoms Cl.
moles MgCl2 present in 5.90 g = grams MgCl2/molar mass MgCl2 = 5.90/95.2 = apprixunately 0.062.
There are 0.062 mols MgCl2 x (6.022 x 10^23 molecules/1 mol) = approximately 3.7E22 molecles MgCl2.
# Cl atoms = approximately 3.7E22 molecules MgCl2 x (2 Cl atoms/1 mol MgCl2) = approximately 3.7E22 x 2 = about 7.4E22 atoms Cl.
Yes, you are correct. I apologize for the oversight in my previous response. Given that 5.90 g of MgCl2 is produced, the calculations you provided are accurate. There are approximately 7.4E22 chlorine atoms present in 5.90 g of MgCl2. Thank you for correcting me.