Question
43.7g of anhydrous CuSO4 were dissolved in water and the solution made up to 2dm^3. What is the minority of the solution
Answers
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To determine the minority of the solution, we need to know the concentration of the solution.
First, we need to calculate the molar mass of anhydrous CuSO4:
CuSO4 = (1 x 63.55 g/mol) + (1 x 32.07 g/mol) + (4 x 15.99 g/mol)
CuSO4 = 159.61 g/mol
Next, we need to calculate the number of moles of CuSO4 present in the solution:
moles = mass/molar mass
moles = 43.7 g / 159.61 g/mol
moles = 0.274 moles
Finally, we can calculate the concentration of the solution (in mol/dm^3 or M):
concentration = moles/volume
concentration = 0.274 mol / 2 dm^3
concentration = 0.137 M
Therefore, the minority of the solution is 0.137 M.
First, we need to calculate the molar mass of anhydrous CuSO4:
CuSO4 = (1 x 63.55 g/mol) + (1 x 32.07 g/mol) + (4 x 15.99 g/mol)
CuSO4 = 159.61 g/mol
Next, we need to calculate the number of moles of CuSO4 present in the solution:
moles = mass/molar mass
moles = 43.7 g / 159.61 g/mol
moles = 0.274 moles
Finally, we can calculate the concentration of the solution (in mol/dm^3 or M):
concentration = moles/volume
concentration = 0.274 mol / 2 dm^3
concentration = 0.137 M
Therefore, the minority of the solution is 0.137 M.