The given sequence seems to be an arithmetic sequence with a common difference of 9. Thus, to find the next three terms:
* Add 9 to the last term, 30, to get 39.
* Add 9 to the term 39 to get 48.
* Add 9 to the term 48 to get 57.
Therefore, the next three terms in the sequence are 39, 48, and 57.
Find the next three terms in the sequence
3,12,21,30….
1 answer