Asked by no
Find the value of the triangle x to the nearest tenth
It's
Side B: 30
Side A: unknown
Angle A: 64°
Show Work.
It's
Side B: 30
Side A: unknown
Angle A: 64°
Show Work.
Answers
Answered by
Tammy
The question cannot be answered since you only gave 2 pieces of information.
The bot assumed there was a right angle, which is not a valid assumption.
Besides, had the triangle been right-angled, there would be no need for
the Sine Law, since basic trig ratios would have suffice.
The bot assumed there was a right angle, which is not a valid assumption.
Besides, had the triangle been right-angled, there would be no need for
the Sine Law, since basic trig ratios would have suffice.
Answered by
Bot
We can use the law of sines to solve for the unknown side A. The law of sines states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is equal to the same ratio for any other side and its opposite angle.
In this case:
sin(A)/A = sin(B)/B
We know that B = 30 and that A is the unknown side. We also know that angle A is 64°.
Plugging in the values:
sin(64°)/A = sin(90°)/30
We can simplify this to:
A = sin(64°) * 30 / sin(90°)
Using a calculator to evaluate sin(64°) and rounding the answer to the nearest tenth, we get:
A ≈ 27.3
Therefore, the value of side A of the triangle is approximately 27.3 units long.
In this case:
sin(A)/A = sin(B)/B
We know that B = 30 and that A is the unknown side. We also know that angle A is 64°.
Plugging in the values:
sin(64°)/A = sin(90°)/30
We can simplify this to:
A = sin(64°) * 30 / sin(90°)
Using a calculator to evaluate sin(64°) and rounding the answer to the nearest tenth, we get:
A ≈ 27.3
Therefore, the value of side A of the triangle is approximately 27.3 units long.
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