Write y−2=32(x+2) in slope-intercept form.

1. y = 3/2x + 5

2. y = 3/2x + 6

3. y = 3/2x + 3/2

4. y =3/2 + 5x

2 answers

To write the equation y−2=32(x+2) in slope-intercept form (y = mx + b), we need to solve for y.

y−2=32(x+2)

First, distribute the 32 to the terms inside the parentheses:

y - 2 = 3x + 6

Next, add 2 to both sides to isolate y:

y = 3x + 8

Now, we have the equation y = 3/2x + 8 in slope-intercept form, where the slope is 3/2 and the y-intercept is 8.

So, the correct answer is option 2: y = 3/2x + 6.
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