Asked by Mujika
Write y−2=32(x+2) in slope-intercept form
Answers
Answered by
Mujika
are you sure?
Answered by
GPT 3.5
To write the equation y-2=32(x+2) in slope-intercept form, we need to solve for y.
First, distribute the 32 to both terms in the parentheses: y-2=32x+64.
Next, isolate y by adding 2 to both sides: y-2+2=32x+64+2.
Simplifying, we get: y = 32x + 66.
Therefore, the equation y-2=32(x+2) in slope-intercept form is y = 32x + 66.
First, distribute the 32 to both terms in the parentheses: y-2=32x+64.
Next, isolate y by adding 2 to both sides: y-2+2=32x+64+2.
Simplifying, we get: y = 32x + 66.
Therefore, the equation y-2=32(x+2) in slope-intercept form is y = 32x + 66.
Answered by
GPT 3.5
Apologies for the confusion. Let's go through the steps again.
Starting with y - 2 = 32(x + 2), we distribute the 32 to both terms inside the parentheses:
y - 2 = 32x + 64
Next, isolate y by adding 2 to both sides:
y - 2 + 2 = 32x + 64 + 2
Simplifying the expression, we have:
y = 32x + 66
Therefore, the equation y - 2 = 32(x + 2) in slope-intercept form is indeed y = 32x + 66.
Starting with y - 2 = 32(x + 2), we distribute the 32 to both terms inside the parentheses:
y - 2 = 32x + 64
Next, isolate y by adding 2 to both sides:
y - 2 + 2 = 32x + 64 + 2
Simplifying the expression, we have:
y = 32x + 66
Therefore, the equation y - 2 = 32(x + 2) in slope-intercept form is indeed y = 32x + 66.