Write y−2=32(x+2) in slope-intercept form

Answer 1

To write the equation y-2=32(x+2) in slope-intercept form, we need to solve for y.

First, distribute the 32 to both terms in the parentheses: y-2=32x+64.

Next, isolate y by adding 2 to both sides: y-2+2=32x+64+2.

Simplifying, we get: y = 32x + 66.

Therefore, the equation y-2=32(x+2) in slope-intercept form is y = 32x + 66.

Answer 2

are you sure?

Answer 3

Apologies for the confusion. Let's go through the steps again.

Starting with y - 2 = 32(x + 2), we distribute the 32 to both terms inside the parentheses:

y - 2 = 32x + 64

Next, isolate y by adding 2 to both sides:

y - 2 + 2 = 32x + 64 + 2

Simplifying the expression, we have:

y = 32x + 66

Therefore, the equation y - 2 = 32(x + 2) in slope-intercept form is indeed y = 32x + 66.