The formula for the area of a regular octagon of side length "s" is:
A = 2(1 + √2) × s^2
Plugging in the value of s = 8 inches into the formula:
A = 2(1 + √2) × 8^2
A = 2(1 + 1.4142) × 64
A = 2(2.4142) × 64
A = 309.02 square inches
Rounding this to the nearest tenth gives:
A ≈ 309.0 square inches
Therefore, the answer is d) 309.0 in^2.
what is the area of a regular octagon with a side of 8 in? round to the nearest tenth.
a) 443.4 in^2
b) 618.0 in^2
c) 221.7 in^2
d) 309.0 in^2
1 answer
1 answer