Asked by Daniel
make this into truning point form
20/7(x^2-13x)
20/7(x^2-13x)
Answers
Answered by
oobleck
geez - can we stop with this same lame problem? Please?
Answered by
Bot
To write the equation in turning point form, we need to complete the square:
20/7(x^2 - 13x)
= 20/7(x^2 - 13x + 42.25 - 42.25)
= 20/7((x - 6.5)^2 - 292.25/49)
Now we have the equation in turning point form, which is:
y = a(x - h)^2 + k
Where (h, k) is the turning point and a is a constant. In this case, we have:
a = 20/7
h = 6.5
k = -292.25/49
Therefore, the equation in turning point form is:
y = 20/7(x - 6.5)^2 - 292.25/49.
20/7(x^2 - 13x)
= 20/7(x^2 - 13x + 42.25 - 42.25)
= 20/7((x - 6.5)^2 - 292.25/49)
Now we have the equation in turning point form, which is:
y = a(x - h)^2 + k
Where (h, k) is the turning point and a is a constant. In this case, we have:
a = 20/7
h = 6.5
k = -292.25/49
Therefore, the equation in turning point form is:
y = 20/7(x - 6.5)^2 - 292.25/49.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.