Question

A number cube is rolled and a coin is tossed. The number cube and the coin are fair. What is the probability that the number rolled is greater than 2 and the coin toss is heads?
Write your answer as a fraction in simplest form.

Answer 1

There is a $\frac{4}{6} = \frac{2}{3}$ probability that the number rolled is greater than 2 since 4, 5, or 6 meet the condition, and there is a $\frac{1}{2}$ probability that the coin toss is heads. So the probability that both events happen is $\frac{2}{3} \times \frac{1}{2} = \boxed{\frac{1}{3}}$.