The probability of an odd number (1,3 or 5) on the first roll is 3/6=1/2
For the second roll, to get a multiple of three (3 or 6) the probability is 2/6=1/3
The two rolls are independent.
So the probability of succeeding both events is (1/2)*(1/3)=1/6
a number cube is rolled twice. what is the probability of rolling an odd number on the first roll and a multiple of three on the second roll?
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