Asked by Sinachi
Express the polar form of zw, z/w and 1/z where; z=4(√3+i), w=-3-3i
Answers
Answered by
oobleck
z = 8 cis30°
w = 3√2 cis225°
zw = 24√2 cis255°
z/w = 4√2/3 cis -195° = 4√2/3 cis165°
1/z = 1/8 cis -30° = 1/8 cis330°
w = 3√2 cis225°
zw = 24√2 cis255°
z/w = 4√2/3 cis -195° = 4√2/3 cis165°
1/z = 1/8 cis -30° = 1/8 cis330°
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