Question

This exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a card is returned to the deck. If you do not put the first card back in the deck before you draw the next, what is the probability that both cards are diamonds?

Answer 1

Again, the bot seems to get the basic idea of the problem, but
then messes up the simplest arithmetic.

(13/52) x (12/51) = 1/17 , not 3/52