Asked by Michael
Solve the system of equations using substitution.
A sorority held a bake sale to raise money and sold brownies and chocolate chip cookies. They priced the brownies at $2 and the chocolate chip cookies at $1. They raised $260 and sold 190 items.
How many brownies and how many cookies were sold?
A sorority held a bake sale to raise money and sold brownies and chocolate chip cookies. They priced the brownies at $2 and the chocolate chip cookies at $1. They raised $260 and sold 190 items.
How many brownies and how many cookies were sold?
Answers
Answered by
Tammy
Enough already with the same question !!!!!
Answered by
Bot
Let's assume that x is the number of brownies sold, and y is the number of chocolate chip cookies sold.
From the given information, we can create a system of equations:
Equation 1: 2x + 1y = 260 (the total amount raised is $260)
Equation 2: x + y = 190 (the total number of items sold is 190)
We can use substitution to solve for one of the variables. Let's solve for y:
y = 190 - x
Now we can substitute y in Equation 1 with 190 - x:
2x + 1(190 - x) = 260
Simplifying this equation, we get:
2x + 190 - x = 260
x + 190 = 260
x = 70
So the sorority sold 70 brownies. We can use Equation 2 to find the number of chocolate chip cookies sold:
y = 190 - x = 190 - 70 = 120
Therefore, the sorority sold 70 brownies and 120 chocolate chip cookies.
From the given information, we can create a system of equations:
Equation 1: 2x + 1y = 260 (the total amount raised is $260)
Equation 2: x + y = 190 (the total number of items sold is 190)
We can use substitution to solve for one of the variables. Let's solve for y:
y = 190 - x
Now we can substitute y in Equation 1 with 190 - x:
2x + 1(190 - x) = 260
Simplifying this equation, we get:
2x + 190 - x = 260
x + 190 = 260
x = 70
So the sorority sold 70 brownies. We can use Equation 2 to find the number of chocolate chip cookies sold:
y = 190 - x = 190 - 70 = 120
Therefore, the sorority sold 70 brownies and 120 chocolate chip cookies.
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