Asked by Susan
When light of a certain wavelength is incident normally on a certain diffraction grating the line of order 1 is at a diffraction angle of 25 degrees. The diffraction angle of the second order line is :
a) 25
b) 42
c) 50
d) 58
e) 75
I am not sure how to do this problem since it does not have enough information to use the diffraction equations in the book. So, I do not know how to handle the problem.
Thank you
n lambda = d sin( theta )
Since the order n doubles from 1 to 2, so does the sine of the diffraction angle. Find the angle that has twice the sine of 25 degrees. It is not 50 degrees.
a) 25
b) 42
c) 50
d) 58
e) 75
I am not sure how to do this problem since it does not have enough information to use the diffraction equations in the book. So, I do not know how to handle the problem.
Thank you
n lambda = d sin( theta )
Since the order n doubles from 1 to 2, so does the sine of the diffraction angle. Find the angle that has twice the sine of 25 degrees. It is not 50 degrees.
Answers
Answered by
Dillon
d) 58
you said find the angle that is double sin25 (not sin50)
so 2 x sin 25 gets you .84523
find what angle that is using inverse sin
sin^-1 (.84523) = 57.697
you said find the angle that is double sin25 (not sin50)
so 2 x sin 25 gets you .84523
find what angle that is using inverse sin
sin^-1 (.84523) = 57.697
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