Asked by allexelle
A photon of light has a wavelength of about 600 nm (1nm = 1 x 10-9 m). What is the energy of this photon of light? Show all calculations leading to an answer.
Answers
Answered by
Damon
find the frequency from the wavelength
lambda = c T = c/f
then energy = Lank constant * frequency
lambda = c T = c/f
then energy = Lank constant * frequency
Answered by
allexelle
ok thank you so much, have a great day :)
Answered by
nisha verma
Given: wavelength=600 nm; h=6.62×10^-34
Solution:
Since, Energy=hc/wavelength
(6.62×10^-34×3.0×10^8)/600×10^-9
=3.39×10^-19J
=3.39×10^-19/1.6×10^-19 eV
=2.11875 eV
Solution:
Since, Energy=hc/wavelength
(6.62×10^-34×3.0×10^8)/600×10^-9
=3.39×10^-19J
=3.39×10^-19/1.6×10^-19 eV
=2.11875 eV
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