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Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate o...Asked by jamalhunter778
Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.(1 point)
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Answered by
River
Two machines at a factory are filling cans of soup. One machine has already filled 180 cans of soup, and fills cans at a rate of 15 per minute. The second machine has already filled 210 cans of soup, and fills cans at a rate of 12 per minute. Write an equation to show when the two machines will have filled the same number of cans of soup. Use x as your variable.
2x+210=15x+180
210−12x=180−15x
12x+180=15x+210
12x−210=15x−180
2x+210=15x+180
210−12x=180−15x
12x+180=15x+210
12x−210=15x−180
Answered by
gurl
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Answered by
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Answered by
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Answered by
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The equation to show when the two machines will have filled the same number of cans of soup is:
180 + 15x = 210 + 12x
where x is the number of minutes it will take for the two machines to fill the same number of cans of soup.
180 + 15x = 210 + 12x
where x is the number of minutes it will take for the two machines to fill the same number of cans of soup.
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